When simplifying the quadratic formula to solve the equation x^2+6x-55=0, the number under the radical sign will be: a)-184b)232c)256

C) 256

Step-by-step explanation:

the quadratic formula: x = (-b +- sqrt (b^2 - 4ac)) / 2a

a is the coficient of x^2: a=1

b is the coeficient of x: b = 6

c is the independent term: c= -55

introducing this values to the quadratic formula we have :

x= ( -6 +- sqrt (6^2 - 4(1)(-55)) ) /2(1)

in the radical sign we have:

6^2 - 4(1)(-55)

=36 + 220

=256

the answer is 45 i just did it on oddesy ware

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