Aquadratic equation is shown below: 9x^2 - 16x + 60 = 0 part a: describe the solution(s) to the equation by just determining the radicand. show your work part b: solve 4x^2 + 8x - 5 = 0 by using an appropriate method. show the steps of your work, and explain why you choose the method used.

the solutions to a general quadratic equation is

X=-b±√b²-4ac/2a  ,, When ax²+bx+c=0

the discriminant is the expression under the radical b²−4ac

Part A:

discriminant is (-16)² - 4(9)(60) = -1904

there are two complex solutions  

Part B:  

4x² + 8x − 5 = 0

4x² + 10x -2x - 5=0

2x ( 2x + 5) - 1(2 x + 5) =0  

(2x + 5)(2x-1) = 0

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2x+5 = 0                 2x-1 =0    

x = -5/2                     x = 1/2

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

step-by-step explanation:

what is the figure? attach a picture.