what is the equation of a line with a slope of −4 and a point (−2, 5) on the line? express the equation in the form of y=mx+b where m is the slope and b is the y-intercept. enter your answer in the box.

y = -4x + 13

Step-by-step explanation:

m = -4, (-2, 5)

you're going to put this into point-slope form, which is y - y1 = m (x - x1).

y - 5 = -4 (x - (-2))

distribute the -4 (and the two negatives make a positive)

y - 5 = -4x + 8

add five on both sides to get y on its own, on the left, adding 5 to the five cancels out five.

and you get:

y = -4x + 13

answer:

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