The left vertex, if the hyperbola opens horizontally, or the bottom vertex, if it opens vertically, is . the other vertex is ?

The center of the hyperbola is (-5,7). The bottom vertex is ( -5, 7 - 5 sqrt(10)). The other vertex is ( -5, 7 + 5 sqrt(10))

Step-by-step explanation:

The equation of the hyperbola is:

-(x+5)^2/9^2+(y-7)^2/13^2=1

This is the same that:

(y-7)^2/13^2-(x+5)^2/9^2=1

This equation has the form:

(y-k)^2/a^2-(x-h)^2/b^2=1

and the hyperbola opens vertically, then the coordinates of the bottom vertex are: (h,k-c). The other vertex is (h,k+c)

Comparing with the form:

-h=5→h=-5

k=7

a^2=13^2

b^2=9^2

c^2=a^2+b^2→c^2=13^2+9^2→c^2=169+81→c^2=250→sqrt(c^2)=sqrt(250)→

c=sqrt(25*10)→c=sqrt(25) sqrt(10)→c=5 sqrt(10)

The bottom vertex is: (h,k-c)=(-5, 7 - 5 sqrt(10))

The other vertex is: (h,k+c)=(-5, 7 + 5 sqrt(10))

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

mx+89b(-98)nb

step-by-step explanation: