Find the discriminant and determine how many solutions the equation has and if they are imaginary or real. show all work. y = 4x^2 - 5x + 1

Discriminant = 9 and the equation has two real solutions

Step-by-step explanation:

For a quadratic equation in the form of y = ax^2 + bx + c, its discriminant is equal to b^2 - 4ac.

If discriminant < 0, then the equation has two imaginary solutions. If it is 0, then the equation has 1 real solution and if it is > 0, 2 real solutions.

In this case, y = 4x^2 - 5x + 1.

So its discriminant = -5^2 - 4*4*1

= 9 so it has two real solutions.

i need a picture

step-by-step explanation: