Given a circle with measures of (c, d, and r) and a circle with measures of (c', d', and r'), what is r' if c/c' = 0.75 and d = 6.0? a) 2 b) 4 c) 8 d) 12

B

Step-by-step explanation:

All circles are similar and therefore proportional. C/C' is the ratio of Circle C to Circle C'. Since it is 0.75, this means that C is 75% of C'. We know that radius of C will also be 75% of the radiuc of C'. We can the radius because we know the diameter of Circle C is 6. The radius is therefore 3. 3 is 75% of 4. So r/r' or 3/4=0.75. r/ must be 4.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

false

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