After being rearranged and simplified, which two of the following equations could be solved using the quadratic formula? a) 5x^3+2x-4=2x^2 b) x^2-6x-7=2x^2 c) 2x^2-3x+10=2x^2+21 d) 5x^2-3x+10=2x^2

B & D

Step-by-step explanation:

The quadratic formula can be used to solve for x for any quadratic. Recall a quadratic is any function whose highest exponent known as degree is 2. Looking at the answer selections, A has one term with exponent 3. This isn't possible in the formula. Looking at answer C, the term with exponent 2 has the same coefficient on each side of the equal sign. When it is rearranged these will cancel out no exponent of 2 will be in the equation anymore. Only B & D work after being rearranged and simplified

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

you bought 31 v bucks

step-by-step explanation:

25+6=31