The larger of two numbers exceeds twice the smaller by one. three times the smaller exceeds the larger by six. if y is the larger number, which of the following systems of equations represents the word problem? y = 2x + 1 and 3x + 6 = y y = 2x + 1 and y + 6 = 3x y = 2(x + 1) and y + 6 = 3x

Step-by-step explanation:

larger number = y

smaller number=x

y>2x+1

y<3x+6

Probably the first one, if I did this right.

To do this problem, you need to know how to read math, literally. The problem says that y is the larger number, so assume the smaller is x. So, y exceeds 2x by 1 (so, y>2x+1). then, it says 3x exceeds y by 6; therefore, 3x+6>y. I may have interpreted it wrong, though, so tell me if I made a mistake :))

first one

the correct answer is x/3+10≥32

hope this !

step-by-step explanation: