In δabc, m∠acb = 90°, cd ⊥ ab and m∠acd = 45°. find ac, if cd = 6 sqrt 3

Step-by-step explanation:

Consider right triangle ABC with right angle ACB. If m∠ACD = 45°, then

m∠BCD=m∠ACB-m∠ACD=90°-45°=45°.

Since  CD ⊥ AB, then

m∠CDA=m∠CDB=90°.

Thus, triangles ACD and BCD are right triangles with right angles ADC and BDC. In these triangles:

m∠CAD=90°-m∠ACD=90°-45°=45°;

m∠CBD=90°-m∠BCD=90°-45°=45°.

Thus, triangles ACD and BCD are isosceles right triangles with

By the Pythagorean theorem,

⊂⊃⊂⊃ω

step-by-step explanation:

i hope this : )

the answer is c just got it on ed

step-by-step explanation: