Determine the standard form of the equation of the line that passes through (-6,6) and (3,-2)

y=(8/9)x + 4 and 2/3

Step-by-step explanation:

the slope of this line:

change in y/change in x

change in y=6-(-2)=8

change in x=-6-3=-9

change in y/change in x= 8/9

8/9 is the slope, so you plug it in for m in the standard form equation. You then use one point's x and y values to substitute for x and y in the equation, and solve for b, which is the y intercept

y=mx+b

y=(8/9)x+b

-2=(8/9)*3+b

-2=8/3+b

-4 and 2/3=b

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

step-by-step explanation: