Solve the following subtraction problems. a. 8 mi. 133 yd. 2 ft. – 5 mi. 107 yd. 2 ft. b. 2 yd. 2 ft. 6 in. – 1 ft. 11 in. c. 6 yd. – 2 ft. 7 in. d. 8 yd. 4 in. – 7 yd. 2 ft. 8 in.

Let's keep in mind the conversion factors between mile, yard, feet and inches:

1 mile = 1760 yards

1 yard = 3 feets

1 feet = 12 inches

a) 3 mi. 26 yd.

We have:

8 mi. 133 yd. 2 ft. –

5 mi. 107 yd. 2 ft =

Here, we can simply do the substraction of each term, and we get:

(8-5) mi  (133-107) yd  (2-2) ft =

3 mi. 26 yd  0 ft =

3 mi. 26 yd.

b) 2 yd. 7 in.

We have:

2 yd. 2 ft. 6 in. –

0 yd.  1 ft. 11 in.

Here, we need to convert 1 feet into 12 inches and add them to the inches in the first term as follows:

2 yd. 2 ft. 6 in. = 2 yd. 1 ft. (6+12) in. = 2 yd. 1 ft. 18 in.

So now the subtraction becomes:

2 yd. 1 ft. 18 in. –

0 yd.  1 ft. 11 in.

and now we can simply do the substraction of each term, and we get:

(2-0) yd.  (1-1) ft.  (18-11) in. =

2 yd. 0 ft. 7 in. =

2 yd. 7 in.

c)  5 yd. 5 in.

We have:

6 yd.  0 ft. 0 in. –

0 yd.  2 ft. 7 in.

We have to "move" 1 yard into  feets and inches in the first term, as follows:

6 yd.  0 ft. 0 in. = 5 yd. 3 ft. 0 in. = 5 yd. 2 ft. 12 in.

And now the subtraction becomes:

5 yd. 2 ft. 12 in. -

0 yd.  2 ft. 7 in. =

5 yd.  0 ft. 5 in. =

5 yd. 5 in.

d) 8 in.

We have:

8 yd. 0 ft. 4 in. –

7 yd. 2 ft. 8 in.

Again, let's convert the first term, moving yards into feets and inches:

8 yd. 0 ft. 4 in. = 7 yd. 3 ft. 4 in. = 7 yd. 2 ft. (4+12) in. = 7 yd. 2 ft. 16 in.

So now the subtraction is:

7 yd. 2 ft. 16 in. -

7 yd. 2 ft. 8 in. =

0 yd. 0 ft. 8 in. =

8 in.