If f(x) =-x2 +6x -1 and g(x)=3x2-4x-1 find f-g (x)

- 4x² + 10x

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

= - x² + 6x - 1 - (3x² - 4x - 1) ← distribute

= - x² + 6x - 1 - 3x² + 4x + 1 ( collect like terms )

= - 4x² + 10x

step-by-step explanation:

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m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°