What is the equation of a line with a slope of 3 and a point (3, 1) on the line? express the equation in the form of y=mx+b where m is the slope and b is the y-intercept. enter your answer in the box.

The equation of the line would be y = 3x - 8

Step-by-step explanation:

To find any equation when you have the slope and a point, start with point-slope form and then solve for y.

y - y1 = m(x - x1)

y - 1 = 3(x - 3)

y - 1 = 3x - 9

y = 3x - 8

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2