Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.

12s - 20 < 50 - 3s - 25

12s - 20 < 50 - 3s - 25
+3s                  +3s
15s  - 20 <   50 - 25
        + 20   + 20    
15s          <   70 - 25

15s          <   45
÷ 15              ÷15
     s         <  3

The value of s is less than or equal to 3. So s can be 3, 2, 1, 0, and negative numbers.

s = 3 ⇒ 12(3) - 20 < 50 - 3(3) - 25 ; 36 - 20 < 50 - 9 - 25 ; 16 < 16
s = 2 ⇒ 12(2) - 20 < 50 - 3(2) - 25 ; 24 - 20 < 50 - 6 - 25 ;   4 < 19

The answer would be 27 because assuming that each package has 1 bar of soap and 1 tube of toothpaste, after 27 packages they would run out of toothpaste