Owen runs a pet store that sells rabbits. he wants to ensure he has more than 1 pound of dry food for every four rabbits he has in the store, and he currently has 5.7 pounds of dry food. write and solve an inequality for the scenario. how many rabbits can owen have in the store? a. owen can have a minimum of 22 rabbits in the store. b. owen can have a maximum of 22 rabbits in the store. c. owen can have a maximum of 23 rabbits in the store. d. owen can have a minimum of 23 rabbits in the store.

B.

Step-by-step explanation:

You would need to look at how much food he has right now, so he has 5.7 lbs, ok. then you need to look at how many rabbits per lbs. You can take 5.7 lbs and times it by 4, because 4 per lb.

5.7 X 4 = 22.8

since  you are looking at rabbits, you can't have .8 of a rabbit. so you would drop the .8 lb, and you would get your answer 22 as the max.

50- 250 is correct i did that one too

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt