Need with asap . which ordered pair is a solution to the linear functions 2x-y 1/3y=x (0,2) (1,3) (2,6) (3,8)

(1,3) & (2,6) are solutions to 1/3y=x. No solution is listed for 2x=y.

Step-by-step explanation:

To find find if an ordered pair is a solution, we can graph the line and look for the point on the line or evaluate the equation with the solution as the variable values.

We will substitute (x,y) for a given solution and find if the equation holds true.

For 2x=y

(0,2)                (1,3)                   (2,6)                  (3,8)

2(0)=2             2(1)=3                2(2)=6              2(3)=8

0=2 FALSE     2=3 FALSE        4=6   FALSE    6=8 FALSE

For 1/3y=x.

(0,2)                   (1,3)                      (2,6)                     (3,8)

1/3(2)=0             1/3(3)=1               1/3(6)=2              1/3(8)=3

2/3=0 FALSE     1=1 TRUE           2=2   TRUE          8/3=3 FALSE

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.