Given: ∆abc, ab = cb bd − median to ac e∈ ab ,f∈ bc ae = cf prove: △ade ≅ △cdf δbde ≅ δbdf

1) By SAS theorem, ΔADE≅ΔCDF

2) By SSS theorem, ΔBDE≅ΔBDF

Step-by-step explanation:

Consider isosceles triangle ABC (see diagram).

1. In triangles ADE and CDF:

By SAS theorem, ΔADE≅ΔCDF.

2. In triangles BDE and BDF:

Be SSS theorem, ΔBDE≅ΔBDF.

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.