What is the equation of a line with a slope of 7 and a point (1, 8) on the line? express the equation in the form of y = mx + b, where m is the slope and b is the y-intercept. enter your answer in the box.

y = 7x + 1

Step-by-step explanation:

If the slope and coordinates have already been given, you can plug the values into the following equation of a line:

y - y1 = m(x - x1)

Where y1 is the y coordinate, so in this case 8,

x1 is the x coordinate which is 1

m is the slope, so 7:

y - 8 = 7(x - 1)

Expand the brackets:

y - 8 = 7x - 7

To isolate the y, we need to move the -8 over to the other side making it a positive 8:

y = 7x - 7 + 8

y = 7x + 1

So the equation of the line is y = 7x + 1

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: