Supposed five plain hamburgers cost the same as three super burgers. also suppose that one super burger cost $.30 more than one cheeseburger wow one plain hamburger cost $.20 less than one cheeseburger. what would be the cost of one of each kind a burger

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

Step-by-step explanation:

We have three conditions

(1) 5P = 3S

(2)  S = C + 0.30

(3)  P = C – 0.20                           Substitute (3) into (1)

(4)   5(C – 0.20) = 3S                   Substitute (2) into (4)

      5(C – 0.20) = 3(C + 0.30)     Remove parentheses

         5C – 1.00 = 3C + 0.90       Add 1.00 to each side

                    5C = 3C + 1.90        Subtract 3C from each side

                    2C = 1.90                 Divide each side by 2

                      C = $0.95              Substitute C into Equation (2)

                      S = 0.95 + 0.30

                      S = $1.25               Substitute C into Equation (3)

                     P = 0.95 – 0.20

                    P = $0.75

1 plain = $0.75; 1 cheese = $0.95; 1 super = $1.25

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2