The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. how long will it take the object to hit the ground ? round to the nearest hundresth of a second?

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0   Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)