One hundred grams of plutonium is stored in a container. the amount p (in grams) of plutonium present after t years can be modeled by the equation: p=100(0.00007)t. how much plutonium is present after 20,000 years?

That equation is not typed correctly.  Radioactivity decreases by what is known as exponential decay.

Pu 239 has a half-life of  24,100 years.  

We need to calculate lambda which is natural log (2) / half-life

lambda = .693147 / 24,100 = 2.876 x 10^-5

Amount remaining = beginning amount • e ^ ( -λ • time )

Amount remaining = 100 * 2.718281828^(-2.876 x 10^-5 * 20,000)

Amount remaining = 100 * 2.718281828^-.5752

Amount remaining = 100 * 0.5625923391

Amount remaining after 20,000 years = 56.25923391 grams

Source: https://www.1728.org/halflif2.htm

Step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )