Aconstruction worker is building a wall. the wall is 17.5 yds long. he needs to place a stud every 15 inches. the first stud has already been placed at one end of the wall. how many additional studs are needed, if the last stud will be placed at the other end of the wall? first fill in the blanks on the left side using the ratios shown. then write your answer.

The correct answers are:

Box-1:

Box-2:

Box-3:

Box-4: 42 studs

Explanation:

Given:

Wall is 17.5 yds long.

In 1 yard, there are 3 feet.

Therefore,

In Box-1, you should put .

In 1 foot, there are 12 inches.

Therefore,

In Box-2, you should put .

He needs to place 1 stud every 15 inches.

Therefore,

In Box-3, you should put .

Now multiple all the numbers, you will get the number of studs.

In Box-4, write 42 studs.

-i

answer: idk wbu

step-by-step explanation: umm..

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9