If h(x) = 3x − 1 and j(x) = −2x, solve h[j(2)] and select the correct answer below.

h[j(2)] =-13    

Step-by-step explanation:

The first step is to solve j(2) by putting x=2 into j(x)

j(2) = -2(2) = -4

Now we put  x= -4 into h(x)

h(-4) = 3(-4) -1

h(-4) = -12-1 = -13

h[j(2)] =-13    

h[j(2)]  = -13.

Step-by-step explanation:

Given  : If h(x) = 3x − 1 and j(x) = −2x,

To find : solve h[j(2)] .

Solution : We have given

 h(x) = 3x − 1 and j(x) = −2x

For x = 2 ,

j (2) = -2 (2).

j(2) = -4 .

h[j(2)]  = h(-4) .

h(4) = 3 (-4) -1 .

h(4) = -12 -1 .

h[j(2)]  = h(4) = -13.

h[j(2)]  = -13.

Therefore, h[j(2)]  = -13.

46.2+112.3

step-by-step explanation: