One integer is 9 less than 5 times another. their product is 18. find the integers.

x = 3   and x=-6/5

Step-by-step explanation:

x = one integer

y = other integer

One integer is 9 less than 5 times another

x= 5y-9

product is 18

xy = 18

Substitute in for x

(5y-9) *y = 18

Distribute

5y*y -9y = 18

5y^2 - 9y = 18

Subtract 18 from each side.

5y^2 - 9y -18= 18-18

5y^2 - 9y -18 = 0

Using the quadratic formula

-b ± sqrt(b^2 -4ac)

2a

-(-9) ±sqrt(9^2 -4*5*(-18))

2(5)

9 ±sqrt(81 +360))

10

9 ±sqrt(441)

10

9±21

10

x = (9+21)/10   and x = (9-21)/10

x = 30/10   and x = (-12)/10

x = 3   and x=-6/5

answer: asdfghjkl,mnbv

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.