Mathematics, 29.06.2019 00:00, lilsnsbsbs
Arectangle has a length of \sqrt[3]{81} and a width of 3^{\frac{2}{3}} inches. find the area of the rectangle.
Answers: 1
![\sqrt[3]{81}](/tpl/images/0029/0000/ec017.png)
and the width is 
. So, to find the area we must replace the values of length and width into the previous expression.![area=(\sqrt[3]{81})\times (3^{\frac{2}{3}})](/tpl/images/0029/0000/550a9.png)
could be written in other way taking into account that 
.
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Arectangle has a length of \sqrt[3]{81} and a width of 3^{\frac{2}{3}} inches. find the area of the...
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