Determine how much water should be mixed with 6 gallons of 55% solution of sulfuric acid to make a 20% solution of sulfuric acid?

10.5 gallons of water should be added.

Step-by-step explanation:

Let , where are the concentration of the solution and are the volume of the solution for i=1,2.

Now, substituting values, we have,

55*6 = 20*

i.e. = (6*55)/20

i.e. = 16.5

So, the final volume is 16.5 gallons.

Hence, we need to add 16.5 - 6 = 10.5 gallons of water.

50

step-by-step explanation: