Acliff diver dives from a cliff height of 70 feet. the equation describing his height during the dive is h = –16t 2 + 70. find the time it takes the diver to be 50 ft above the water.

1.118 seconds

Step-by-step explanation:

h =50

h = –16t^2 + 70

substitute h=50

50 = –16t^ 2 + 70

subtract 70 from each side

50 - 70 = -16t^2

-20 = -16 t^2

divide each side by -16

-20/-16 = t^2

1.25 = t^2

take the square root of each side

sqrt(1.25) = sqrt(t)

we only take the positive because time can only be positive

1.118  =t

4

step-by-step explanation: