Asap pls the distance it takes a truck to stop can be modeled by the function in the image d = stopping distance in feet v = initial velocity in miles per hour f = a constant related to friction when the truck's initial velocity on dry pavement is 40 mph, its stopping distance is 138 ft. determine the value of f, rounded to the nearest hundredth.

Here, we are required to determine the value of f, rounded to the nearest hundredth.

Therefore, by making f the subject of the formular in the function,

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f = .39

Step-by-step explanation:

d (v) = 2.15 v^2 / (64.4 f)

v = 40

d = 138

substitute these in

138 = 2.15 (40)^2 / (64.4 *f)

simplify

138 = 2.15 (*1600) / (64.4 *f)

138 = 3440 / (64.4 *f)

multiply each side by 64.4f

138 * 64.4 f = 3440

8887.2 f = 3440

divide by 8887.2

8887.2 f /8887.2= 3440/8887.2

f=.38707

to the nearest hundredth

f = .39

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

2y+y=5

add 2y and y