What is the equation of the line, in slope-intercept form, that is perpendicular to the line with the equation y=6x−1 and passes through the point (−6,4)?

Greetings!

y =

Step-by-step explanation:

First, we must find the slope of the current equation.

This is the number in front of the x.

Seeing as this is 6x, the slope of this line is 6

When finding the slope of a line perpendicular, you need to find the

So, in this case it is:

The negatives cancel out which leave

So the gradient is

Now, to find the equation of a line, you need to use:

y - y1 = m(x - x1)

Where y1 and x1 are the values in the coordinates (-6 , 4)

So y1  = 4, x1 = -6, and m is . Plug these values in:

y - 4 =

We need to get rid of the fraction so we multiply the whole equation by 6 (6 * 1/6 = 1):

6y - 24 = - (x - 2)

The minus outside the bracket means that every value inside the bracket is oposite:

6y - 24 = -x + 2

And now simply move the -24 over to the other side, making it a positive:

6y = -x +2 + 26

Simplify:

6y = -x + 28

Divide all values by 6 to get y:

y =

So the equation of the line is y =

Hope this helps!

Okay so for every triangle has three angles that always add up to 180 degrees. and to tell the difference between whether they are secure, right or obtuse is that acute: has one angle that is less than 90 degrees. right triangle means there is at least one angle that is exactly 90 degrees. and an obtuse angle has an angle that is bigger than 180 degrees. i’ll do #13 as an example: 13. 40 and 50 so if every triangle has 180 degrees 40+50= 90 degrees then180-90= 90 degrees so the third angle is 90 degrees and because this triangle has a 90 degree angle it means it is a right triangle

X=y+4 is the answe