Asilk ribbon costs $5.60 for 0.8m. find the constant of variation.

The constant of variation value of 7.

Step-by-step explanation: We are given cost of 0.8 meter of a silk ribbon = $5.60.

Let us assume y be the total cost for x meter of a silk ribbon and k is the  constant of variation.

So, we can set up an equation for proportion relationship:

y = k x.

Let us plug x=0.8 and y= 5.60, in above proportion relationship equation, we get

5.60 = k (0.8).

Dividing both sides by 0.8, we get

5.60/0.8 = k(0.8)/0.8

k =7.

Therefore, the constant of variation value of 7.

im a goose

step-by-step explanation:

gg5

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.