The answer written in the box is not correct. if you know this trigonometry/pythagoras question

18.55

Step-by-step explanation:

Step One

Find AC

Formula

a^2 + b^2 = c^2

Givens

a = 70b = 50c = AC

Solution

AC^2 = 70^2 + 50^2                Substitute into PythagorasAC^2 = 4900 + 2500               Expand   AC^2 = 7400                             combineAC = sqrt(7400)                         Take the square root of both sides.AC = 86.02

Step Two

Find FC

Givens

<BCF = 30o                                          GivenBC    =  50                                            GivenFC =                                                      Find

Formula

Tan(30) = FC/50

Solution

FC = 50 * tan(30)

FC = 28.87

Step Three

Find <FAC

FC = 28.87

AC = 86.02

Tan(<FAC) = FC / AC

Tan(<FAC) = 28.87/86.02

Tan(<FAC) = 0.33558

<FAC = Tan-1(0.33558)

<FAC = 18.55 which is just about what you got.

The coordinates of point a right now is (-3,-1) you have to multiply these coordinates by a factor of 2 to get (-6,-2)