What are the two solutions of 2x^2=-x^2-5x-1

x = 5/-6 + (√13)/-6

x = 5/-6 -(√13)/-6

Step-by-step explanation:

2x^2 = -x^2 - 5x - 1. Subtract 2x^2 from both sides.

-3x^2 - 5x - 1. Do the quadratic formula.

That gives you:

-5/6 ± (√13)/-6.

i'm pretty sure it's c. nvm

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)