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![8x^4+24x^3-27x-81=8x^3(x+3)-27(x+3)\\\\=(x+3)(8x^3-27)=(x+3)(2^3x^3-3^3)=(x+3)[(2x)^3-3^3]\\\\\text{use}\ a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=(x+3)(2x-3)[(2x)^2+(2x)(3)+3^2]\\\\=\boxed{(x+3)(2x-3)(4x^2+6x+9)}](/tpl/images/0030/4625/f8e7d.png)
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