Find the equation of a parabola with vertex at the origin and focus (0, -32). y^2= -128x x^2= -32y x^2= 128y x^2=-128y

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.