Write the equation of the line perpendicular to 2x+3y=9 that passes through (-2,5). write your answer in slope-intercept form. show work .

First find the slope of the first line. The line is in standard form, Ax + By = C, and slope is given by -A/B. Therefore, the slope of 2x+3y=9 is -2/3.

Now, if lines are perpendicular, their slopes are the negative reciprocals of each other. So, the slope of the line you want to find is the reciprocal of -2/3  (-3/2) multiplied by -1, or 3/2.

To find the equation of the line, we can use point-slope form because we have a point (-2, 5), and a slope that we calculated (3/2). Point-slope form is y-y₁=m(x-x₁) where (x₁, y₁) is a point and m is the slope. Our point is (-2, 5) so x₁ = -2 and y₁ = 5. Our slope is 3/2. Now, simply plug the values into the formula: y-5=3/2(x-(-2)). To convert the equation from point slope form to slope-intercept form, simply isolate y and get rid of parenthesis by distributing.

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled

nope lol

step-by-step explanation: