Which is the equation of a parabola with vertex (0,0), that opens to the right and has a focal width of 8?

Equation of parabola:

Step-by-step explanation:

A parabola with vertex (0,0), that opens to the right.

The general equation of parabola open right whose vertex (0,0)

Focal width : Two points opposite to the the focus on parabola.

Distance between these two points is called focal width i,e 4p

Focal width = 8

So, 4p=8

p=2

Focus: (2,0)

Equation of parabola:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.