Chapman’s brickyard sells bricks and blocks. a brick costs $0.38 and a block costs $1.56. the brickyard filled a $24.80 order, which contained 28 items a. write a system of equations that can be used to find the number of bricks and blocks in the order. b. how many blocks were in the order?

a)

b) 12 blocks and 16 bricks.

Step-by-step explanation:

Let x represent the number of bricks and y represent the number of blocks.  Each brick costs $0.38; this gives us the expression 0.38x.  Each block costs $1.56; this gives us the expression 1.56y.  Together they totaled $24.80; this gives us the equation

0.38x + 1.56y = 24.80

We also know that the number of bricks, x, added to the number of blocks, y, totaled 28; this gives us

x + y = 28

To solve this, we will use substitution.  First we will isolate x in the second equation by subtracting y from each side:

x + y = 28

x + y - y = 28 - y

x = 28 - y

Now we substitute this in place of x in the first equation:

0.38(28 - y) + 1.56y = 24.80

Using the distributive property, we have

0.38(28) - 0.38(y) + 1.56y = 24.80

10.64 - 0.38y + 1.56y = 24.80

Combining like terms gives us

10.64 + 1.18y = 24.80

Subtract 10.64 from each side:

10.64 + 1.18y - 10.64 = 24.80 - 10.64

1.18y = 14.16

Divide both sides by 1.18:

1.18y/1.18 = 14.16/1.18

y = 12

There were 12 blocks sold.

Substituting this into the second equation gives us

x + 12 = 28

Subtract 12 from each side:

x + 12 - 12 = 28 - 12

x = 16

There were 16 bricks sold.

i think the answer is b)

step-by-step explanation: