Answers: 2
![\bf \begin{cases} 4x-2y=5\\[1em] 4x+y=-4\implies \boxed{y}=-4-4x \end{cases} \\\\\\ \stackrel{\textit{plugging in \boxed{y} in the 1st equation}}{4x-2\left( \boxed{-4-4x} \right)=5}\implies 4x+8+8x=5 \\\\\\ 12x=-3\implies x=\cfrac{-3}{12}\implies \blacktriangleright x=-\cfrac{1}{4} \blacktriangleleft](/tpl/images/0031/8737/f74bf.png)
![\bf \boxed{y}=-4-4x\implies y=-4-4\left( -\cfrac{1}{4} \right)\implies y=-4+1\implies \blacktriangleright y=-3 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left( -\frac{1}{4}~~,~~-3 \right)~\hfill](/tpl/images/0031/8737/6f891.png)
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Solve the system 4x-2y=5 and 4x+y=-4...
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