Given the position function s(t), s(t) = t2 + 3t + 1, where s is measured in meters and t is in seconds, find the velocity and acceleration of the particle at t = 4 seconds. (5 points) 11 m/sec; 2 m/sec2 2 m/sec; 0 m/sec2 11 m/sec; 0 m/sec2 12 m/sec; 2 m/sec2

  11 m/s; 2 m/sec²

Step-by-step explanation:

v(t) = s'(t) = 2t +3

v(4) = 2·4 +3 = 11 . . . m/s

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a(t) = v'(t) = 2 . . . . m/s²

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Velocity and acceleration are 11 m/s and 2 m/s².

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2