Why is the product of two rational numbers always rational? select from the drop-down menus to correctly complete the proof. let a/b and c/d represent two rational numbers. this means a, b, c, and d are and b and d are not 0. the product of the numbers ac/bd, where bd is not 0. both ac and bd are and bd is not 0. because ac/bd is the ratio of two the product is a rational number. blank 1: a. integers b. irrational numbers blank 2: a. integers b. irrational numbers blank 3: a. integers b. irrational numbers pls answer ! 30 !

all three blanks are integers

Step-by-step explanation:

Let a/b and c/d represent two rational numbers. This means a, b, c, and d are _integers, and b and d are not 0. The product of the numbers ac/bd, where bd is not 0. Both ac and bd are  integers, and bd is not 0. Because ac/bd is the ratio of two integers, the product is a rational number.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

step-by-step explanation:

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