The sum of three consecutive odd numbers is 63. what is the smallest of these numbers?

The smallest number = 19

Step-by-step explanation:

We'll call X the smallest of those odd numbers

Then x + (x+2) + (x+4) = 63

X + X + 2 + X + 4 = 63

3X + 6 = 63

3X = 63 - 6 = 57

X = 57/3 = 19

The three consecutives odd numbers are 19, 21, 23

The sum = 19+21+23 = 63

Your answer : The smallest number = 19



x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3