Will mark ! find tan θ if cos θ = one divided by four and sin θ < 0. a. negative square root of fifteen b.4 c. negative square root of fifteen divided by fifteen d. negative square root of seventeen

-3.872983346

Step-by-step explanation:

In this case we have: cos θ = 1/4 Whose possible solutions are: θ = 2 * pi * n - Acos (1/4) θ = 2 * pi * n + Acos (1/4) Where, n belongs to the natural numbers. As sin θ <0 then the solution is: θ = 2 * pi * n - Acos (1/4) For n = 1 we get: θ = 4.965069236 radians Thus: tan θ = tan (4.965069236) = - 3.872983346 tan θ = -3.872983346

A. negative square root of fifteen

Step-by-step explanation:

In this case we have: cos θ = 1/4 Whose possible solutions are: θ = 2 * pi * n - Acos (1/4) θ = 2 * pi * n + Acos (1/4) Where, n belongs to the natural numbers. As sin θ <0 then the solution is: θ = 2 * pi * n - Acos (1/4) For n = 1 we get: θ = 4.965069236 radians Thus: tan θ = tan (4.965069236) = - 3.872983346 tan θ = -3.872983346 = negative square root of fifteen

THE GUY/GIRL BEFORE ANSWERED CORRECTLY

all you had to do was put each answer into google and see which = to -3.872983346. Next time at least try doing some work...

it's both, now can you answer my most recent question?