Which postulate can be used to prove that abd and cbd are congruent given that bd and ac and bd bisects ac sas sss asa ssa

SAS

Step-by-step explanation:

Here we are given two situations:

BD⊥AC

This indicates that angle ADB and CDB are 90 degrees.

Aso we are given that BD bisects AC.

This indicates that AD=DC

So in triangles ADB and CDB , we have

BD=BD (common) (Side)

angle ADB= angle CDB (Angle)

AD=DC (side)

So the two triangles are congruent by SAS congruency.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!