Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0

x = pi, 3pi, 5pi  etc

x = -pi, -3pi, -5pi etc

Step-by-step explanation:

cos^2 x + 2 cos x + 1 = 0

replace cos x with m

m^2 + 2m +1 = 0

solve by factoring  (this is a^2 +2ab+b^2 = (a+b)^2  where a =m and b=1)

(m+1)^2=0

take the square root of each side

m+1 =0

m=-1

now replace m with cos x

cos x = -1

take arccos  of each side

arccos cos x = arccos (-1)

x = pi, 3pi, 5pi  etc

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

-4, -2, 1, 4

step-by-step explanation:

domain = x values

range = y values