The probability of students choosing the left lunch line at school is p=0.431. find the variance of the binomial distribution of 982 students choosing the left lunch line today.

We are given the probability of students choosing the left lunch line at school is

We have to find the variance of the binomial distribution of 982 students choosing the left lunch line today.

Therefore, n = 982

We know that the variance of Binomial distribution is:

                rounded to 2 decimal places

Therefore, the variance of the binomial distribution of 982 students choosing the left lunch line today is 240.82

283 square feet

step-by-step explanation:

good luck

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3