Tickets to a school play cost $2 if bought in advance, and $3 if bought at the door. by selling all 400 of their tickets, $1030 was collected. let x represent the number of tickets sold at the door. in terms of x how many of the tickets were sold in advance?

230 were sold at the door

170 were sold in advance

Step-by-step explanation:

*i dont know if this is the proper way to do it but it has the correct answer

x=at door y=in advance

x+y=400

3x+2y=1030

y=-x+400

2y=-3x+1030

y=-3/2x+515

-x+400=-3/2x+515

x=230 y=170

230 tickets were sold at door and 170 tickets were sold in advance.

Step-by-step explanation:

Let x represent the number of tickets sold at the door.

Let y be the tickets sold in advance.

Equations form as per given scenario are:

or x=400-y       ......(1)

     ......(2)

Substituting the value of x from (1) in (2)

=>

=>

We get y = 170

And x = = 230

Hence, 230 tickets were sold at door and 170 tickets were sold in advance.

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?