How do i solve 1/3h-4(2/3h-3)=2/3h-6

6.. I think

Step-by-step explanation:

h in (-oo:+oo)

(1/3)*h-(4*((2/3)*h-3)) = (2/3)*h-6 // - (2/3)*h-6

(1/3)*h-(4*((2/3)*h-3))-((2/3)*h)+6 = 0

(1/3)*h-4*((2/3)*h-3)+(-2/3)*h+6 = 0

h/3-4*(2/3*h-3)+(-2*h)/3+6 = 0

(-4*3*(2/3*h-3))/3+h/3+(-2*h)/3+(3*6)/3 = 0

h-4*3*(2/3*h-3)-2*h+3*6 = 0

18-7*h-2*h+36 = 0

18-9*h+36 = 0

54-9*h = 0

(54-9*h)/3 = 0

(54-9*h)/3 = 0 // * 3

54-9*h = 0

54-9*h = 0 // - 54

-9*h = -54 // : -9

h = -54/(-9)

h = 6    

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify