Factorising quadratics[tex]12x^{2} +x-15=(6x+/tex]find the missing numbers. i'm not entirely sure if this is possible, as my teacher is prone to making typos but i have no idea how to solve this; i've tried trial and error with factors of 15 and none of them seem to work!

Step-by-step explanation:

A short answer is that you cannot factor this the way you are trying to do it. What to do to go on is a question. You could use the quadratic formula to get some sort of answer but if factoring is your only option, forget about it.

Here's how you can check.

There is a part of the quadratic solution is the sqrt(b^2 - 4*a*c). In order to be factorable, this sqrt must result in a perfect square.

sqrt(1 - 4(12)(-15) ) = sqrt( 1 - - 720) = sqrt(721)

This is anything but a perfect square. (721 does factor, however, into 7 * 103). I03 is prime. So the long and short of it is, there's no way it will factor.

y do u put "subscirbe to ence" on a app for ppl who need with their work?

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,