Find the vertex of this parabola y=-4x^2-8x-7

(-1, -3)

Step-by-step explanation:

The standard form of a quadratic function is  

y = ax² + bx + c

The vertex form is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b/(2a) and k = f(h)

In the equation y= -4x² - 8x -7

a = -4; b = -8; c = -7

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Calculate h

h = -(-8)/[2(-4)]

h = 8/(-8)

h = -1

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Calculate k

k = -4(-1)² -8(-1) -7

k = -4 +8 -7

k = -3

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The vertex is at (-1, -3).

The graph is an inverted parabola with its vertex at (-1, -3).

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

6: 07 is your answer

step-by-step explanation: