Ididn’t find equation in point slope form for the line parallel to y=1/2x-7 that passes through (-3,-2)

y +2 = (1/2)(x +3)

Step-by-step explanation:

It is helpful to know that the point-slope form of the equation with slope m through point (h, k) is ...

... y -k = m(x -h)

You have a line with a slope of 1/2. The parallel line will also have a slope of 1/2, so m = 1/2. The point you want on your line is (-3, -2), so (h, k) = (-3, -2). Putting these values into the point-slope form gives you ...

... y -(-2) = (1/2)(x -(-3))

Simplifying this gives ...

... y +2 = (1/2)(x +3)